The evolution of AI language models has set new standards, especially in the coding and programming landscape. Leading the charge are DeepSeek-V3, GPT-4o, and Llama 3.3 70B, each offering unique advantages. In this blog, we will do an AI language model comparison, focusing on the architectures, parameters, coding capabilities, and practical use cases of GPT-4o and its two alternatives. Through a detailed analysis of DeepSeek-V3 vs GPT-4o vs Llama 3.3 70B, I will uncover which model is best suited for programming tasks and how these advancements are shaping the future of AI in 2025.
DeepSeek-V3 is an open-source AI model that excels in large language model benchmarks with its efficient Mixture-of-Experts (MoE) architecture. Llama 3.3 70B is impressive with its scalability and adaptability, making it a strong contender in AI model parameter comparison. Meanwhile, GPT-4o stands out with its extensive resources, giving its competitors a run for their money.
Now, let’s begin our comparison by understanding the design and architectures of the three models.
DeepSeek-V3 is an open-source Mixture-of-Experts (MoE) model with 671 billion parameters, activating 37 billion parameters per token. It leverages cutting-edge load balancing and multi-token prediction methods, trained on 14.8 trillion tokens. Achieving top-tier performance across multiple benchmarks, the model maintains training efficiency with a cost of only 2.788 million H800 GPU hours.
DeepSeek-V3 incorporates reasoning abilities from DeepSeek-R1 Lite and offers a 128K context window. Moreover, it can process a variety of input types, including text, structured data, and complex multimodal inputs, making it versatile for diverse use cases.
Also Read: Building AI Application with DeepSeek-V3
GPT-4o is an advanced language model developed by OpenAI, featuring state-of-the-art architectural improvements. It is trained over a vast dataset of input tokens, making it highly capable across various tasks with impressive accuracy.
The model supports multimodal inputs and has enhanced reasoning abilities, providing versatility for numerous applications. With a context window of 128K tokens, it can generate up to 16,384 tokens per request and processes around 77.4 tokens per second. Released in August 2024, its knowledge extends up to October 2023, making it one of the most powerful and adaptable models on the market.
The Meta Llama 3.3 70 B multilingual large language model (LLM) is an open-source, pre-trained, instruction-tuned generative model with 70 billion parameters. It is designed to be optimized for efficiency and scalability. It employs cutting-edge techniques to handle a broad range of tasks, trained on over 15 trillion tokens.
Llama 3.3 70B is an auto-regressive language model that uses an optimized transformer architecture. The model achieves remarkable performance on several benchmarks, keeping training costs minimal with optimized resource allocation.
Llama 3.3 70B supports a wide context window and incorporates advanced reasoning capabilities for nuanced and precise task handling. It is designed to process text-based inputs but can also handle structured data, offering flexibility in various applications.
Benchmark | Description | DeepSeek-V3 | GPT-4o | Llama 3.3 70B |
MMLU | Massive Multitask Language Understanding- Test knowledge across 57 subjects including maths, history, law and more | 88.5% | 88.7% | 88.5% |
MMLU-Pro | A more robust MMLU benchmark with more complex reasoning focused questions and reduced prompt sensitivity | 75.9% | 74.68% | 75.9% |
MMMU | Massive Multitask Multimodal Understanding: Text understanding across text, audio,images and videos | Not available | 69.1% | Not available |
HellaSwag | A challenging sentence completion benchmark | 88.9% | Not available | Not available |
HumanEval | Evaluates code generation and problem solving capabilities | 82.6% | 90.2% | 88.4% |
MATH | Tests Mathematical problem solving abilities across various difficulty levels | 61.6% | 75.9% | 77% |
GPQA | Test PhD-level knowledge in physics, chemistry and biology that require domain expertise | 59.1% | 53.6% | 50.5% |
IFEval | Test model’s ability to accurately follow explicit formatting instructions, generate appropriate outputs and maintain consistent instructions | 86.1% | Not available | 92.1% |
You can find the results of their individual benchmark tests here:
Speaking of pricing, GPT-4o is roughly 30x more expensive compared to DeepSeek-V3 for input and output tokens. Meanwhile, Llama 3.3 70B Instruct is roughly 1.5x more expensive compared to DeepSeek-V3 for input and output tokens.
DeepSeek-V3 excels in benchmarks that require structured task completion, such as MMLU (Massive Multitask Language Understanding), and HumanEval (Code Generation). However, it faces challenges in benchmarks like MATH (Mathematical Problem-Solving), where its performance is not as competitive. It also leads in GPQA (Generalized Passage Question Answering), outperforming the other models in this domain.
GPT-4o performs particularly well in HumanEval and MMLU, where it stands out with its ability to generate high-quality responses across various topics. While it shines in reasoning-based tasks, it struggles in specialized areas such as MATH and GPQA, where other models perform better.
Llama 3.3 70B shows its strengths in benchmarks like MATH and IFEval (Instruction Following Evaluation). It demonstrates superior problem-solving abilities and follows complex instructions more effectively than the other models. Its performance in other benchmarks like HumanEval and GPQA is less impressive than DeepSeek-V3 and GPT-4o.
Now we will compare the code writing capabilities of DeepSeek-V3, GPT-4o, and Llama 3.3 70B. For that, we are going to give the same prompt to all three models and evaluate their responses on the below metrics:
Prompt: “Hi, you are an excellent code instructor so help me with this question.
Q. Write Python code for finding the Factorial of a Large Number.”
To compute the factorial of a large number using an array (to manually handle multiplication and carry operations), here’s a Python implementation:
def multiply(arr, x):
"""
Multiplies an array representation of a number with an integer x.
: param arr: List of integers representing the digits of the number.
: param x: Integer to multiply with.
:return: Updated array with the result.
"""
carry = 0 # Initialize carry
for i in range(len(arr)):
prod = arr[i] * x + carry
arr[i] = prod % 10 # Store last digit of the product in the array
carry = prod // 10 # Update the carry
# Process carry, add digits to the array
while carry > 0:
arr.append(carry % 10)
carry //= 10
return arr
def factorial_large_number_array(n):
"""
Calculate the factorial of a large number using array representation.
: param n: Integer for which the factorial is to be computed.
:return: Factorial of n as a string.
"""
if n < 0:
return "Factorial is not defined for negative numbers."
if n == 0 or n == 1:
return "1"
arr = [1] # Initialize the array with the first factorial value (1)
for x in range(2, n + 1):
arr = multiply(arr, x)
# The result is stored in reverse order in the array
return ''.join(map(str, reversed(arr)))
# Input a large number
try:
number = int(input("Enter a large number to calculate its factorial: "))
result = factorial_large_number_array(number)
print(f"The factorial of {number} is:\n{result}")
except ValueError:
print("Invalid input! Please enter a valid integer.")
Here’s a Python code snippet that calculates the factorial of a large number using an array to store the digits.
def multiply(x, res, res_size):
"""Multiplies x with the number represented by res[]"""
carry = 0
for i in range(res_size):
prod = res[i] * x + carry
res[i] = prod % 10
carry = prod // 10
while carry:
res.append(carry % 10)
carry = carry // 10
def factorial(n):
""" Calculates the factorial of a number n"""
res = [1]
res_size = 1
for i in range(2, n + 1):
multiply(i, res, res_size)
res_size = len(res)
return res
def print_factorial(n):
""" Prints the factorial of a number n"""
res = factorial(n)
print("Factorial of", n, "is:")
for digit in reversed(res):
print(digit, end="")
# Example usage:
n = 55
print_factorial(n)
To calculate the factorial of a large number using an array in Python, we can store the result in an array (or list) to handle very large numbers that exceed the limit of standard data types. Here’s how you can implement it:
def factorial(n):
# Initialize the result as a list with 1
result = [1]
# Multiply the result list with numbers from 2 to n
for x in range(2, n + 1):
carry = 0
# Multiply each digit in the result list with x
for i in range(len(result)):
product = result[i] * x + carry
result[i] = product % 10 # Store the last digit
carry = product // 10 # Carry over the remaining digits
# Add the remaining carry to the result list
while carry > 0:
result.append(carry % 10)
carry = carry // 10
# Reverse the result list to get the correct order
result.reverse()
return result
# Input: Number to find factorial of
n = int(input("Enter a number: "))
# Compute factorial
factorial_result = factorial(n)
# Convert the list of digits to a string for display
factorial_str = ''.join(map(str, factorial_result))
# Output the result
print(f"Factorial of {n} is: {factorial_str}")
GPT-4o’s response is the most complete, balancing efficiency, readability, and robust error handling. It includes detailed comments and clear variable names, and handles invalid input gracefully, making it well-suited for practical use or collaborative development.
Llama 3.3 70B’s response is functional, but it lacks proper error handling and detailed documentation. Its structure is less intuitive, and the use of redundant variables impacts the efficiency. This makes it the weakest of the three.
DeepSeek-V3’s response is efficient and cleanly structured but lacks robust error handling and sufficient documentation. It is a strong contender but falls short in clarity for people to follow or adapt easily.
Prompt: ‘‘Hi, you are an excellent code instructor so help me with this question.
Q. Given a string s, return true if the s can be palindrome after deleting at most one character from it.’’
To solve this problem, we can use a two-pointer approach to check if the string can be a palindrome after removing at most one character. Here’s the Python implementation
def valid_palindrome(s):
"""
Check if the string can become a palindrome by removing at most one character.
: param s: The input string.
:return: True if the string can become a palindrome, otherwise False.
"""
def is_palindrome_range(left, right):
# Helper function to check if a substring is a palindrome
while left < right:
if s[left] != s[right]:
return False
left += 1
right -= 1
return True
left, right = 0, len(s) - 1
while left < right:
if s[left] != s[right]:
# If a mismatch occurs, check by skipping one character
return is_palindrome_range(left + 1, right) or is_palindrome_range(left, right - 1)
left += 1
right -= 1
return True
# Example Usage
s1 = "abca"
print(f"Input: {s1}\nOutput: {valid_palindrome(s1)}")
s2 = "defgd"
print(f"Input: {s2}\nOutput: {valid_palindrome(s2)}")
Here’s a Python solution that checks if a string can be a palindrome after deleting at most one character.
def valid_palindrome(s: str) -> bool:
"""
Returns True if the string can be a palindrome after deleting at most one character.
:param s: The input string.
:return: True if the string can be a palindrome, False otherwise.
"""
def is_palindrome(i, j):
"""
Checks if the substring from index i to j is a palindrome.
:param i: The start index.
:param j: The end index.
:return: True if the substring is a palindrome, False otherwise."""
while i < j:
if s[i] != s[j]:
return False
i += 1
j -= 1
return True
i, j = 0, len(s) - 1
while i < j:
if s[i] != s[j]:
# If a mismatch is found, try deleting one character
return is_palindrome(i + 1, j) or is_palindrome(i, j - 1)
i += 1
j -= 1
return True
print(valid_palindrome("abca"))
print(valid_palindrome("defgd"))
To solve this problem, we need to check if a string can become a palindrome by deleting at most one character. A palindrome reads the same forwards and backward. Here’s how we can approach this:
def validPalindrome(s: str) -> bool:
def is_palindrome(s, left, right): # Helper function to check if a substring is a palindrome
while left < right:
if s[left] != s[right]:
return False
left += 1
right -= 1
return True
left = 0
right = len(s) - 1
while left < right:
if s[left] != s[right]:
# Try deleting either the left or the right character
return is_palindrome(s, left + 1, right) or is_palindrome(s, left, right - 1)
left += 1
right -= 1
return True
# Example usage:
s1 = "abca"
print(validPalindrome(s1))
s2 = "defgd"
print(validPalindrome(s2))
GPT-4o’s response is the most complete and well-documented. It handles the core functionality with clarity, making it easy for future developers to modify or extend the code. Its combination of efficiency and clear documentation makes it ideal for production environments.
Llama 3.3 70B’s response is a functional solution but lacks the clear variable naming and in-depth documentation found in GPT-4o. The lack of comments within the main logic makes it harder to follow, and there is room for improvement in terms of readability. However, it is efficient enough for small tasks where quick implementation is the priority.
DeepSeek-V3’s response strikes a good balance between efficiency and simplicity but falls short in documentation. It’s concise and quick but lacks enough detail for others to follow the code easily. Its approach can be beneficial in scenarios where time and resources are limited, but it would need more thorough explanations and error handling to make the code production-ready.
GPT-4o outperforms both Llama 3.3 70B and DeepSeek-V3 in terms of efficiency, clarity, error management, and comprehensive documentation. This makes it the top choice for both practical applications and educational purposes. While Llama 3.3 70B and DeepSeek-V3 are functional, they fall short due to the lack of robust error handling and clear documentation. Adding proper error management, improving variable naming, and including detailed comments would elevate their usability to match GPT-4o’s standard.
Also Read:
A. GPT-4o excels in real-world coding due to its efficient error handling, clear documentation, and well-organized code structure, making it the best choice for practical use.
A. GPT-4o stands out for its readability, offering clear variable names and thorough comments. In comparison, Llama 3.3 70B and DeepSeek-V3 are functional but lack the same level of clarity and documentation, which can make them harder to follow.
A. GPT-4o is the ideal choice for education, providing in-depth documentation and detailed explanations that help learners grasp the underlying logic of the code.
A. To elevate their performance, both models should focus on implementing robust error handling, using more descriptive variable names, and adding detailed comments and documentation to improve their readability and overall usability.